integral of 1 x 3-2x 2

How would you integrate 2x/(x-3)^2? - Yahoo! Answers.
Yahoo! Answers - Integral of 1/ sqrt(3+2x-x^2)?

Integration - Calculus 2 - Fac.hsu.edu.

comparing the coefficients x 2l=2 -2l+m=-1 then l=1 -2(1)+m=-1 m=0 then 2x-1=1( 2x-2)+0 2x-1=2(x-1) given integral=∫2(x-1)/x^2-2x+5.dx.
((x^2+2x-1)/(2x^3+3x^2-2x)) = ((x^2+2x-1)/[x(2x^2+3x-2)) ] = ((x^2+2x-1)/[x(x+2)( 2x-1) then partial fractions. A/x + B/(x + 2) + C/(2x - 1) should do it, try.
5x(2x2+1) 3 dx. Eliminate the variable x, leaving an integral in u only.. Making the correct substitutions above transforms the integral 4x(3x2+3)1/2 dx to which.
First cmplete the square under the radical. Then let u = x–1. An arcsin function will become evident. See http://www.wolframalpha.com/input/?i=Int….
(x^3 + x)e^(x^2) / (x^2 + 1)^2 - xe^(x^2) / (x^2 + 1)^2 = x e^(x^2) / (x^2 + 1) - xe^(x ^2) / (x^2 + 1)^2 = (1/2) [2x e^(x^2) * 1/(x^2 + 1) + e^(x^2).
Integral of (2x^3)/(x^3-1)dx? - Yahoo!
comparing the coefficients x 2l=2 -2l+m=-1 then l=1 -2(1)+m=-1 m=0 then 2x-1=1( 2x-2)+0 2x-1=2(x-1) given integral=∫2(x-1)/x^2-2x+5.dx.
((x^2+2x-1)/(2x^3+3x^2-2x)) = ((x^2+2x-1)/[x(2x^2+3x-2)) ] = ((x^2+2x-1)/[x(x+2)( 2x-1) then partial fractions. A/x + B/(x + 2) + C/(2x - 1) should do it, try.

Integral: x/(sqrt(3-2x-x^2) dx? - Yahoo! Answers.

2 ln (2x) vx - 4 vx + C. Answered by Anonymous 2 minutes later. Not yet rated. integral=ln2/x^2 + ln(x)/x^2 =-ln2/x - 1/x =-(ln2+1)/x. Answered by Anonymous 3.

integral of 1 x 3-2x 2

How would I integrate (2x-1)/(x^2-2x+5)? - Yahoo!
Integral ((x^3)(e^(x^2)) / ((x^2)+1)^2? - Yahoo! Answers.


Integral of (6x+1)/(x^2+2x+3)? - Yahoo!

integral of 1 x 3-2x 2